Editing Electric potential (section)

== Common formulas==
{| class="wikitable"
|+
!Charge configuration
!Figure
! colspan="2" |Electric potential
|-
|Infinite wire
| [[File:Charged infinite wire problem.svg|frameless|235x235px]]
| colspan="2" |<math>V = -\frac{\lambda}{2\pi\varepsilon_0}\ln x,</math> 

where <math>\lambda</math> is uniform linear charge density.
|-
|Infinitely large surface
|[[File:Charged infinite plane problem.svg|frameless|235x235px]]
| colspan="2" |<math>V = -\frac{\sigma x}{2\varepsilon_0},</math>
where <math>\sigma</math> is uniform surface charge density.
|-
|Infinitely long cylindrical volume
|[[File:Charged infinite cylinder problem.svg|frameless|235x235px]]
| colspan="2" |<math>V = -\frac{\lambda}{2\pi\varepsilon_0}\ln x, </math>
where <math>\lambda</math> is uniform linear charge density.
|-
|Spherical volume
|[[File:Charged solid sphere problem.svg|frameless|235x235px]]
|<math>V = \frac{Q}{4\pi\varepsilon_0x}, </math> 
outside the sphere, where <math>Q</math> is the total charge uniformly distributed in the volume.
|<math>V = \frac{Q(3R^2-r^2)}{8\pi\varepsilon_0R^3},</math>
inside the sphere, where <math>Q</math> is the total charge uniformly distributed in the volume.
|-
|Spherical surface
|[[File:Charged spherical surface problem.svg|frameless|235x235px]]
|<math>V = \frac{Q}{4\pi\varepsilon_0x},</math> 
outside the sphere, where <math>Q</math> is the total charge uniformly distributed on the surface.
|<math>V = \frac{Q}{4\pi\varepsilon_0R},</math> 
inside the sphere for uniform charge distribution.
|-
|Charged Ring
|[[File:Charged ring problem.svg|frameless|235x235px]]
| colspan="2" | <math>V = \frac{Q}{4\pi\varepsilon_0\sqrt{R^2+x^2}},</math> 
on the axis, where <math>Q</math> is the total charge uniformly distributed on the ring.
|-
|Charged Disc
|[[File:Charged disc problem.svg|frameless|235x235px]]
| colspan="2" | <math>V = \frac{\sigma}{2\varepsilon_0} \left[\sqrt{x^2+R^2} - x\right],</math>
on the axis, where <math>\sigma</math> is the uniform surface charge density.
|-
|Electric Dipole
|[[File:Electric dipole - axial and equatorial problem.svg|frameless|235x235px]]
| <math>V = 0,</math>

on the equatorial plane.
| <math>V = \frac{p}{4\pi\varepsilon_0x^2},</math>

on the axis (given that <math>x \gg d</math>), where <math>x</math> can also be negative to indicate position at the opposite direction on the axis, and <math>p</math> is the magnitude of [[electric dipole moment]].
|}