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===Quadratic equation=== Consider the [[quadratic equation]] :<math>x^2 - 4x + 1 = 0. </math> By using the [[Quadratic equation#Quadratic formula and its derivation|quadratic formula]], we find that the two roots are :<math>\begin{align} A &= 2 + \sqrt{3},\\ B &= 2 - \sqrt{3}. \end{align}</math> Examples of algebraic equations satisfied by {{math|''A''}} and {{math|''B''}} include :<math>A + B = 4, </math> and :<math>AB = 1. </math> If we exchange {{math|''A''}} and {{math|''B''}} in either of the last two equations we obtain another true statement. For example, the equation {{math|''A'' + ''B'' {{=}} 4}} becomes {{math|''B'' + ''A'' {{=}} 4}}. It is more generally true that this holds for ''every'' possible [[algebraic equation|algebraic relation]] between {{math|''A''}} and {{math|''B''}} such that all [[coefficients]] are [[rational number|rational]]; that is, in any such relation, swapping {{math|''A''}} and {{math|''B''}} yields another true relation. This results from the theory of [[symmetric polynomial]]s, which, in this case, may be replaced by formula manipulations involving the [[binomial theorem]]. One might object that {{math|''A''}} and {{math|''B''}} are related by the algebraic equation {{math|''A'' β ''B'' β 2{{sqrt|3}} {{=}} 0}}, which does not remain true when {{math|''A''}} and {{math|''B''}} are exchanged. However, this relation is not considered here, because it has the coefficient {{math|β2{{sqrt|3}}}} which is [[Quadratic irrational#Square root of non-square is irrational|not rational]]. We conclude that the Galois group of the polynomial {{math|''x''<sup>2</sup> β 4''x'' + 1}} consists of two permutations: the [[Permutation#Circular permutations|identity]] permutation which leaves {{math|''A''}} and {{math|''B''}} untouched, and the [[transposition (mathematics)|transposition]] permutation which exchanges {{math|''A''}} and {{math|''B''}}. As all groups with two elements are [[group isomorphism|isomorphic]], this Galois group is isomorphic to the [[multiplicative group]] {{math|{{mset|1, β1}}}}. A similar discussion applies to any quadratic polynomial {{math|''ax''<sup>2</sup> + ''bx'' + ''c''}}, where {{math|''a''}}, {{math|''b''}} and {{math|''c''}} are rational numbers. * If the polynomial has rational roots, for example {{math|''x''<sup>2</sup> β 4''x'' + 4 {{=}} (''x'' β 2)<sup>2</sup>}}, or {{math|''x''<sup>2</sup> β 3''x'' + 2 {{=}} (''x'' β 2)(''x'' β 1)}}, then the Galois group is trivial; that is, it contains only the identity permutation. In this example, if {{math|''A'' {{=}} 2}} and {{math|''B'' {{=}} 1}} then {{math|''A'' β ''B'' {{=}} 1}} is no longer true when {{math|''A''}} and {{math|''B''}} are swapped. * If it has two [[irrational number|irrational]] roots, for example {{math|''x''<sup>2</sup> β 2}}, then the Galois group contains two permutations, just as in the above example.
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