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== Operator matrix in eigenbasis == {{Main|Transformation matrix#Finding the matrix of a transformation|Eigenvalues and eigenvectors}} As explained in [[transformation matrix#Finding the matrix of a transformation|determining coefficients of operator matrix]], there is a special basis, {{math|'''e'''<sub>1</sub>, ..., '''e'''<sub>''n''</sub>}}, for which the matrix {{math|'''A'''}} takes the diagonal form. Hence, in the defining equation <math display="inline">\mathbf{Ae}_j = \sum_i a_{i,j} \mathbf e_i</math>, all coefficients {{mvar|a{{sub|i, j}}}} with {{math|''i'' β ''j''}} are zero, leaving only one term per sum. The surviving diagonal elements, {{mvar|a{{sub|i, j}}}}, are known as '''eigenvalues''' and designated with {{mvar|λ{{sub|i}}}} in the equation, which reduces to <math>\mathbf{Ae}_i = \lambda_i \mathbf e_i.</math> The resulting equation is known as '''eigenvalue equation'''<ref>{{cite book |last=Nearing |first=James |year=2010 |title=Mathematical Tools for Physics |url=http://www.physics.miami.edu/nearing/mathmethods |chapter=Chapter 7.9: Eigenvalues and Eigenvectors |publisher=Dover Publications |chapter-url= http://www.physics.miami.edu/~nearing/mathmethods/operators.pdf |access-date=January 1, 2012|isbn=978-0486482125}}</ref> and used to derive the [[characteristic polynomial]] and, further, [[eigenvalues and eigenvectors]]. In other words, the [[eigenvalue]]s of {{math|diag(''Ξ»''<sub>1</sub>, ..., ''Ξ»''<sub>''n''</sub>)}} are {{math|''Ξ»''<sub>1</sub>, ..., ''Ξ»''<sub>''n''</sub>}} with associated [[eigenvectors]] of {{math|'''e'''<sub>1</sub>, ..., '''e'''<sub>''n''</sub>}}.
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