Jump to content
Main menu
Main menu
move to sidebar
hide
Navigation
Main page
Recent changes
Random page
Help about MediaWiki
Special pages
Niidae Wiki
Search
Search
Appearance
Create account
Log in
Personal tools
Create account
Log in
Pages for logged out editors
learn more
Contributions
Talk
Editing
Fundamental theorem of algebra
(section)
Page
Discussion
English
Read
Edit
View history
Tools
Tools
move to sidebar
hide
Actions
Read
Edit
View history
General
What links here
Related changes
Page information
Appearance
move to sidebar
hide
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
===Topological proofs=== [[File:Koreny.gif|thumb|right|Animation illustrating the proof on the polynomial <math>x^5-x-1</math>|150x150px]] Suppose the minimum of |''p''(''z'')| on the whole complex plane is achieved at ''z''<sub>0</sub>; it was seen at the proof which uses Liouville's theorem that such a number must exist. We can write ''p''(''z'') as a polynomial in ''z'' β ''z''<sub>0</sub>: there is some natural number ''k'' and there are some complex numbers ''c<sub>k</sub>'', ''c''<sub>''k'' + 1</sub>, ..., ''c<sub>n</sub>'' such that ''c<sub>k</sub>'' β 0 and: :<math>p(z)=p(z_0)+c_k(z-z_0)^k+c_{k+1}(z-z_0)^{k+1}+ \cdots +c_n(z-z_0)^n.</math> If ''p''(''z''<sub>0</sub>) is nonzero, it follows that if ''a'' is a ''k''<sup>th</sup> root of β''p''(''z''<sub>0</sub>)/''c<sub>k</sub>'' and if ''t'' is positive and sufficiently small, then |''p''(''z''<sub>0</sub> + ''ta'')| < |''p''(''z''<sub>0</sub>)|, which is impossible, since |''p''(''z''<sub>0</sub>)| is the minimum of |''p''| on ''D''. For another topological proof by contradiction, suppose that the polynomial ''p''(''z'') has no roots, and consequently is never equal to 0. Think of the polynomial as a map from the complex plane into the complex plane. It maps any circle |''z''| = ''R'' into a closed loop, a curve ''P''(''R''). We will consider what happens to the [[winding number]] of ''P''(''R'') at the extremes when ''R'' is very large and when ''R'' = 0. When ''R'' is a sufficiently large number, then the leading term ''z<sup>n</sup>'' of ''p''(''z'') dominates all other terms combined; in other words, :<math>\left | z^n \right | > \left | a_{n-1} z^{n-1} + \cdots + a_0 \right |.</math> When ''z'' traverses the circle <math>Re^{i\theta}</math> once counter-clockwise <math>(0\leq \theta \leq 2\pi),</math> then <math>z^n=R^ne^{in\theta}</math> winds ''n'' times counter-clockwise <math>(0\leq \theta \leq 2\pi n)</math> around the origin (0,0), and ''P''(''R'') likewise. At the other extreme, with |''z''| = 0, the curve ''P''(0) is merely the single point ''p''(0), which must be nonzero because ''p''(''z'') is never zero. Thus ''p''(0) must be distinct from the origin (0,0), which denotes 0 in the complex plane. The winding number of ''P''(0) around the origin (0,0) is thus 0. Now changing ''R'' continuously will [[homotopy|deform the loop continuously]]. At some ''R'' the winding number must change. But that can only happen if the curve ''P''(''R'') includes the origin (0,0) for some ''R''. But then for some ''z'' on that circle |''z''| = ''R'' we have ''p''(''z'') = 0, contradicting our original assumption. Therefore, ''p''(''z'') has at least one zero.
Summary:
Please note that all contributions to Niidae Wiki may be edited, altered, or removed by other contributors. If you do not want your writing to be edited mercilessly, then do not submit it here.
You are also promising us that you wrote this yourself, or copied it from a public domain or similar free resource (see
Encyclopedia:Copyrights
for details).
Do not submit copyrighted work without permission!
Cancel
Editing help
(opens in new window)
Search
Search
Editing
Fundamental theorem of algebra
(section)
Add topic