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===Fourier series=== {{Main|Fourier series}} The Fourier transform of a periodic function, <math>s_{_P}(t),</math> with period <math>P,</math> becomes a [[Dirac comb]] function, modulated by a sequence of complex [[coefficients]]''':''' :<math>S[k] = \frac{1}{P}\int_{P} s_{_P}(t)\cdot e^{-i2\pi \frac{k}{P} t}\, dt, \quad k\in\Z,</math> (where <math>\int_{P}</math> is the integral over any interval of length <math>P</math>). The inverse transform, known as '''Fourier series''', is a representation of <math>s_{_P}(t)</math> in terms of a summation of a potentially infinite number of harmonically related sinusoids or [[complex exponentials|complex exponential]] functions, each with an amplitude and phase specified by one of the coefficients''':''' :<math>s_{_P}(t)\ \ =\ \ \mathcal{F}^{-1}\left\{\sum_{k=-\infty}^{+\infty} S[k]\, \delta \left(f-\frac{k}{P}\right)\right\}\ \ =\ \ \sum_{k=-\infty}^\infty S[k]\cdot e^{i2\pi \frac{k}{P} t}.</math> Any <math>s_{_P}(t)</math> can be expressed as a [[periodic summation]] of another function, <math>s(t)</math>''':''' :<math>s_{_P}(t) \,\triangleq\, \sum_{m=-\infty}^\infty s(t-mP),</math> and the coefficients are proportional to samples of <math>S(f)</math> at discrete intervals of <math>\frac{1}{P}</math>''':''' :<math>S[k] =\frac{1}{P}\cdot S\left(\frac{k}{P}\right).</math>{{efn-ua |<math>\int_{P} \left(\sum_{m=-\infty}^{\infty} s(t-mP)\right) \cdot e^{-i2\pi \frac{k}{P} t} \,dt = \underbrace{\int_{-\infty}^{\infty} s(t) \cdot e^{-i2\pi \frac{k}{P} t} \,dt}_{\triangleq\, S\left(\frac{k}{P}\right)}</math> }} Note that any <math>s(t)</math> whose transform has the same discrete sample values can be used in the periodic summation. A sufficient condition for recovering <math>s(t)</math> (and therefore <math>S(f)</math>) from just these samples (i.e. from the Fourier series) is that the non-zero portion of <math>s(t)</math> be confined to a known interval of duration <math>P,</math> which is the frequency domain dual of the [[Nyquist–Shannon sampling theorem]]. See [[Fourier series]] for more information, including the historical development.
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