Editing Droop quota (section)

==Example in STV==
The following election has 3 seats to be filled by [[single transferable vote]]. There are 4 candidates: [[George Washington]], [[Alexander Hamilton]], [[Thomas Jefferson]], and [[Aaron Burr]]. There are 102 voters, but two of the votes are [[Spoilt vote|spoiled]].

The total number of valid votes is 100, and there are 3 seats. The Droop quota is therefore <math display="inline"> \frac{100}{3+1} = 25 </math>.<ref name="gallagher-1992"/> These votes are as follows:

{| class="wikitable"
!
!45 voters
!20 voters
!25 voters
!10 voters
|-
!1
|Washington
|Burr
|Jefferson
|Hamilton
|-
!2
|Hamilton
|Jefferson
|Burr
|Washington
|-
!3
|Jefferson
|Washington
|Washington
|Jefferson
|}

First preferences for each candidate are tallied:
* '''Washington''': 45 {{Tick}}
* '''Hamilton''': 10
* '''Burr''': 20
* '''Jefferson''': 25

Only Washington has strictly more than 25 votes. As a result, he is immediately elected. Washington has 20 [[excess vote]]s that can be transferred to their second choice, Hamilton. The tallies therefore become:
* '''Washington''': 25 {{Tick}}
* '''Hamilton''': 30{{Tick}}
* '''Burr''': 20
* '''Jefferson''': 25

Hamilton is elected, so his excess votes are redistributed. Thanks to Hamilton's support, Jefferson receives 30 votes to Burr's 20 and is elected.

If all of Hamilton's supporters had instead backed Burr, the election for the last seat would have been exactly tied, requiring a tiebreaker; generally, ties are broken by taking the [[limit (mathematics)|limit]] of the results as the quota approaches the exact Droop quota.