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== Asymptotic identities == === [[Pronic_number|Pronic numbers]] === As a consequence of the [[#Harmonic_number_difference|harmonic number difference]], the natural logarithm is [[Asymptotic analysis|asymptotically]] approximated by a finite [[Series (mathematics)|series]] difference,<ref name="Deveci2022DoubleSeries"/> representing a truncation of the [[#Riemann_Sum|integral]] at <math>k = n</math>: :<math>H_{{2T[n]}} - H_n \sim \ln(n+1)</math> where <math>T[n]</math> is the {{mvar|n}}th [[triangular number]], and <math>2T[n]</math> is the sum of the [[Pronic_number#As_figurate_numbers|first {{mvar|n}} even integers]]. Since the {{mvar|n}}th [[pronic number]] is asymptotically equivalent to the {{mvar|n}}th [[Square number|perfect square]], it follows that: :<math>H_{{n^2}} - H_n \sim \ln(n+1)</math> === [[Prime number theorem]] === The [[Prime_number_theorem#Statement|prime number theorem]] provides the following asymptotic equivalence: :<math>\frac{n}{\pi(n)} \sim \ln n</math> where <math>\pi(n)</math> is the [[Prime-counting function|prime counting function]]. This relationship is equal to:<ref name="Deveci2022DoubleSeries"/>{{rp|2}} :<math>\frac{n}{H(1, 2, \ldots, x_n)} \sim \ln n</math> where <math>H(x_1, x_2, \ldots, x_n)</math> is the [[harmonic mean]] of <math>x_1, x_2, \ldots, x_n</math>. This is derived from the fact that the difference between the <math>n</math>th harmonic number and <math>\ln n</math> asymptotically approaches a [[Euler's constant|small constant]], resulting in <math>H_{{n^2}} - H_n \sim H_n</math>. This behavior can also be derived from the [[#Logarithm_of_a_power|properties of logarithms]]: <math>\ln n</math> is half of <math>\ln n^2</math>, and this "first half" is the natural log of the root of <math>n^2</math>, which corresponds roughly to the first <math>\textstyle \frac{1}{n}</math>th of the sum <math>H_{n^2}</math>, or <math>H_n</math>. The asymptotic equivalence of the first <math>\textstyle \frac{1}{n}</math>th of <math>H_{n^2}</math> to the latter <math>\textstyle \frac{n-1}{n}</math>th of the series is expressed as follows: :<math>\frac{H_n}{H_{n^2}} \sim \frac{\ln \sqrt{n}}{\ln n} = \frac{1}{2}</math> which generalizes to: :<math>\frac{H_n}{H_{n^k}} \sim \frac{\ln \sqrt[k]{n}}{\ln n} = \frac{1}{k}</math> :<math>k H_n \sim H_{n^k}</math> and: :<math>k H_n - H_n \sim (k - 1) \ln(n+1)</math> :<math>H_{{n^k}} - H_n \sim (k - 1) \ln(n+1)</math> :<math>k H_n - H_{{n^k}} \sim (k - 1) \gamma</math> for fixed <math>k</math>. The correspondence sets <math>H_n</math> as a [[Unit_of_measurement|unit magnitude]] that partitions <math>H_{n^k}</math> across powers, where each interval <math>\textstyle \frac{1}{n}</math> to <math>\textstyle \frac{1}{n^2}</math>, <math>\textstyle \frac{1}{n^2}</math> to <math>\textstyle \frac{1}{n^3}</math>, etc., corresponds to one <math>H_n</math> unit, illustrating that <math>H_{n^k}</math> forms a [[Harmonic_series_(mathematics)#Definition_and_divergence|divergent series]] as <math>k \to \infty</math>. === Real Arguments === These approximations extend to the real-valued domain through the [[Harmonic_number#Alternative,_asymptotic_formulation|interpolated harmonic number]]. For example, where <math>x \in \mathbb{R}</math>: :<math>H_{{x^2}} - H_x \sim \ln x</math> === [[Stirling number|Stirling numbers]] === The natural logarithm is asymptotically related to the harmonic numbers by the [[Stirling_numbers_of_the_first_kind#Asymptotics|Stirling numbers]]<ref>{{cite arXiv | title = New series identities with Cauchy, Stirling, and harmonic numbers, and Laguerre polynomials | author = Khristo N. Boyadzhiev | year = 2022 | eprint = 1911.00186 | pages = 2, 6 | class = math.NT }}</ref> and the [[Gregory_coefficients#Bounds_and_asymptotic_behavior|Gregory coefficients]].<ref>{{cite book | last = Comtet | first = Louis | title = Advanced Combinatorics | publisher = Kluwer | year = 1974 }}</ref> By representing <math>H_n</math> in terms of [[Harmonic_number#Identities_involving_harmonic_numbers|Stirling numbers of the first kind]], the harmonic number difference is alternatively expressed as follows, for fixed <math>k</math>: :<math>\frac{s(n^k+1, 2)}{(n^k)!} - \frac{s(n+1, 2)}{n!} \sim (k-1) \ln(n+1)</math>
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