Jump to content
Main menu
Main menu
move to sidebar
hide
Navigation
Main page
Recent changes
Random page
Help about MediaWiki
Special pages
Niidae Wiki
Search
Search
Appearance
Create account
Log in
Personal tools
Create account
Log in
Pages for logged out editors
learn more
Contributions
Talk
Editing
Hyperbola
(section)
Page
Discussion
English
Read
Edit
View history
Tools
Tools
move to sidebar
hide
Actions
Read
Edit
View history
General
What links here
Related changes
Page information
Appearance
move to sidebar
hide
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
===Equation=== If Cartesian coordinates are introduced such that the origin is the center of the hyperbola and the ''x''-axis is the major axis, then the hyperbola is called ''east-west-opening'' and :the ''foci'' are the points <math>F_1=(c,0),\ F_2=(-c,0)</math>,{{sfn|Protter|Morrey|1970|p=310}} :the ''vertices'' are <math>V_1=(a, 0),\ V_2=(-a,0)</math>.{{sfn|Protter|Morrey|1970|p=310}} For an arbitrary point <math>(x,y)</math> the distance to the focus <math>(c,0)</math> is <math display="inline">\sqrt{(x-c)^2 + y^2}</math> and to the second focus <math display="inline">\sqrt{(x+c)^2 + y^2}</math>. Hence the point <math>(x,y)</math> is on the hyperbola if the following condition is fulfilled <math display="block">\sqrt{(x-c)^2 + y^2} - \sqrt{(x+c)^2 + y^2} = \pm 2a \ .</math> Remove the square roots by suitable squarings and use the relation <math>b^2 = c^2-a^2</math> to obtain the equation of the hyperbola: <math display="block">\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \ .</math> This equation is called the [[canonical form]] of a hyperbola, because any hyperbola, regardless of its orientation relative to the Cartesian axes and regardless of the location of its center, can be transformed to this form by a change of variables, giving a hyperbola that is [[congruence (geometry)|congruent]] to the original (see [[#Quadratic equation|below]]). The axes of [[symmetry (geometry)|symmetry]] or ''principal axes'' are the ''transverse axis'' (containing the segment of length 2''a'' with endpoints at the vertices) and the ''conjugate axis'' (containing the segment of length 2''b'' perpendicular to the transverse axis and with midpoint at the hyperbola's center).{{sfn|Protter|Morrey|1970|p=310}} As opposed to an ellipse, a hyperbola has only two vertices: <math>(a,0),\; (-a,0)</math>. The two points <math>(0,b),\; (0,-b)</math> on the conjugate axes are ''not'' on the hyperbola. It follows from the equation that the hyperbola is ''symmetric'' with respect to both of the coordinate axes and hence symmetric with respect to the origin. ====Eccentricity==== For a hyperbola in the above canonical form, the [[eccentricity (mathematics)|eccentricity]] is given by <math display="block">e=\sqrt{1+\frac{b^2}{a^2}}.</math> Two hyperbolas are [[similarity (geometry)|geometrically similar]] to each other β meaning that they have the same shape, so that one can be transformed into the other by [[translation (geometry)|rigid left and right movements]], [[rotation (mathematics)|rotation]], [[reflection (mathematics)|taking a mirror image]], and scaling (magnification) β if and only if they have the same eccentricity.
Summary:
Please note that all contributions to Niidae Wiki may be edited, altered, or removed by other contributors. If you do not want your writing to be edited mercilessly, then do not submit it here.
You are also promising us that you wrote this yourself, or copied it from a public domain or similar free resource (see
Encyclopedia:Copyrights
for details).
Do not submit copyrighted work without permission!
Cancel
Editing help
(opens in new window)
Search
Search
Editing
Hyperbola
(section)
Add topic