Jump to content
Main menu
Main menu
move to sidebar
hide
Navigation
Main page
Recent changes
Random page
Help about MediaWiki
Special pages
Niidae Wiki
Search
Search
Appearance
Create account
Log in
Personal tools
Create account
Log in
Pages for logged out editors
learn more
Contributions
Talk
Editing
Chinese remainder theorem
(section)
Page
Discussion
English
Read
Edit
View history
Tools
Tools
move to sidebar
hide
Actions
Read
Edit
View history
General
What links here
Related changes
Page information
Appearance
move to sidebar
hide
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
===Hermite interpolation=== [[Hermite interpolation]] is an application of the Chinese remainder theorem for univariate polynomials, which may involve moduli of arbitrary degrees (Lagrange interpolation involves only moduli of degree one). The problem consists of finding a polynomial of the least possible degree, such that the polynomial and its first [[derivative]]s take given values at some fixed points. More precisely, let <math>x_1, \ldots, x_k</math> be <math>k</math> elements of the ground [[field (mathematics)|field]] <math>K,</math> and, for <math>i=1,\ldots, k,</math> let <math>a_{i,0}, a_{i,1}, \ldots, a_{i,r_i-1}</math> be the values of the first <math>r_i</math> derivatives of the sought polynomial at <math>x_i</math> (including the 0th derivative, which is the value of the polynomial itself). The problem is to find a polynomial <math>P(X)</math> such that its ''j''{{hairsp}}th derivative takes the value <math>a_{i,j} </math> at <math>x_i,</math> for <math>i=1,\ldots,k</math> and <math>j=0,\ldots,r_j.</math> Consider the polynomial :<math>P_i(X) = \sum_{j=0}^{r_i - 1}\frac{a_{i,j}}{j!}(X - x_i)^j.</math> This is the [[Taylor polynomial]] of order <math>r_i-1</math> at <math>x_i</math>, of the unknown polynomial <math>P(X).</math> Therefore, we must have :<math>P(X)\equiv P_i(X) \pmod {(X-x_i)^{r_i}}.</math> [[Converse (logic)|Conversely]], any polynomial <math>P(X) </math> that satisfies these <math>k</math> congruences, in particular verifies, for any <math>i=1, \ldots, k</math> :<math>P(X)= P_i(X) +o(X-x_i)^{r_i-1} </math> therefore <math>P_i(X)</math> is its Taylor polynomial of order <math> r_i - 1</math> at <math>x_i</math>, that is, <math>P(X)</math> solves the initial Hermite interpolation problem. The Chinese remainder theorem asserts that there exists exactly one polynomial of degree less than the sum of the <math>r_i,</math> which satisfies these <math>k</math> congruences. There are several ways for computing the solution <math>P(X).</math> One may use the method described at the beginning of {{slink||Over univariate polynomial rings and Euclidean domains}}. One may also use the constructions given in {{slink||Existence (constructive proof)}} or {{slink||Existence (direct proof)}}.
Summary:
Please note that all contributions to Niidae Wiki may be edited, altered, or removed by other contributors. If you do not want your writing to be edited mercilessly, then do not submit it here.
You are also promising us that you wrote this yourself, or copied it from a public domain or similar free resource (see
Encyclopedia:Copyrights
for details).
Do not submit copyrighted work without permission!
Cancel
Editing help
(opens in new window)
Search
Search
Editing
Chinese remainder theorem
(section)
Add topic