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==In rings in general== Unlike in an integral domain, a square root in an arbitrary (unital) ring need not be unique up to sign. For example, in the ring <math>\mathbb{Z}/8\mathbb{Z}</math> of integers [[modular arithmetic|modulo 8]] (which is commutative, but has zero divisors), the element 1 has four distinct square roots: Β±1 and Β±3. Another example is provided by the ring of [[quaternion]]s <math>\mathbb{H},</math> which has no zero divisors, but is not commutative. Here, the element β1 has [[quaternion#Square roots of β1|infinitely many square roots]], including {{math|Β±''i''}}, {{math|Β±''j''}}, and {{math|Β±''k''}}. In fact, the set of square roots of {{math|β1}} is exactly<math display="block">\{ai + bj + ck \mid a^2 + b^2 + c^2 = 1\} .</math> A square root of 0 is either 0 or a zero divisor. Thus in rings where zero divisors do not exist, it is uniquely 0. However, rings with zero divisors may have multiple square roots of 0. For example, in <math>\mathbb{Z}/n^2\mathbb{Z},</math> any multiple of {{mvar|n}} is a square root of 0.
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