Jump to content
Main menu
Main menu
move to sidebar
hide
Navigation
Main page
Recent changes
Random page
Help about MediaWiki
Special pages
Niidae Wiki
Search
Search
Appearance
Create account
Log in
Personal tools
Create account
Log in
Pages for logged out editors
learn more
Contributions
Talk
Editing
Commutator subgroup
(section)
Page
Discussion
English
Read
Edit
View history
Tools
Tools
move to sidebar
hide
Actions
Read
Edit
View history
General
What links here
Related changes
Page information
Appearance
move to sidebar
hide
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
== Commutators == {{main|Commutator}} For elements <math>g</math> and <math>h</math> of a group ''G'', the [[commutator]] of <math>g</math> and <math>h</math> is <math>[g,h] = g^{-1}h^{-1}gh</math>. The commutator <math>[g,h]</math> is equal to the [[identity element]] ''e'' if and only if <math>gh = hg</math> , that is, if and only if <math>g</math> and <math>h</math> commute. In general, <math>gh = hg[g,h]</math>. However, the notation is somewhat arbitrary and there is a non-equivalent variant definition for the commutator that has the inverses on the right hand side of the equation: <math>[g,h] = ghg^{-1}h^{-1}</math> in which case <math>gh \neq hg[g,h]</math> but instead <math>gh = [g,h]hg</math>. An element of ''G'' of the form <math>[g,h]</math> for some ''g'' and ''h'' is called a commutator. The identity element ''e'' = [''e'',''e''] is always a commutator, and it is the only commutator if and only if ''G'' is abelian. Here are some simple but useful commutator identities, true for any elements ''s'', ''g'', ''h'' of a group ''G'': * <math>[g,h]^{-1} = [h,g],</math> * <math>[g,h]^s = [g^s,h^s],</math> where <math>g^s = s^{-1}gs</math> (or, respectively, <math> g^s = sgs^{-1}</math>) is the [[Conjugacy class|conjugate]] of <math>g</math> by <math>s,</math> * for any [[Group homomorphism|homomorphism]] <math>f: G \to H </math>, <math>f([g, h]) = [f(g), f(h)].</math> The first and second identities imply that the [[Set (mathematics)|set]] of commutators in ''G'' is closed under inversion and conjugation. If in the third identity we take ''H'' = ''G'', we get that the set of commutators is stable under any [[endomorphism]] of ''G''. This is in fact a generalization of the second identity, since we can take ''f'' to be the conjugation [[automorphism]] on ''G'', <math> x \mapsto x^s </math>, to get the second identity. However, the product of two or more commutators need not be a commutator. A generic example is [''a'',''b''][''c'',''d''] in the [[free group]] on ''a'',''b'',''c'',''d''. It is known that the least order of a finite group for which there exists two commutators whose product is not a commutator is 96; in fact there are two nonisomorphic groups of order 96 with this property.<ref>{{harvtxt|Suárez-Alvarez}}</ref>
Summary:
Please note that all contributions to Niidae Wiki may be edited, altered, or removed by other contributors. If you do not want your writing to be edited mercilessly, then do not submit it here.
You are also promising us that you wrote this yourself, or copied it from a public domain or similar free resource (see
Encyclopedia:Copyrights
for details).
Do not submit copyrighted work without permission!
Cancel
Editing help
(opens in new window)
Search
Search
Editing
Commutator subgroup
(section)
Add topic